pyslk.get_resource_tape

pyslk.get_resource_tape(resource_path: str | Path) → dict[int, str] | None

returns tape on which resource with given path is stored on

Parameters:

resource_path (str or path-like) – namespace or resource

Returns:

tape(s) on which a file is/are stored on as dict; None otherwise

Return type:

dict[int, str] or None